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Nicole has x dimes and y nickels. She has at least 15 coins worth a maximum of $1
combined. Solve this system of inequalities graphically and determine one possible
solution.

Respuesta :

Answer:

Step-by-step explanation:

[tex]X + Y \geq 15\\\\10X + 5Y \leq 100[/tex]

we want to put it into terms of Y

[tex]y \geq 15 - x\\and\\5y \leq 100 - 10x\\y \leq 20 - 2x[/tex]

the graph is in the attached image. Any point in the shaded overlap region where x is greater than or equal to 0 (assuming you cannot have negative coins) works, e.g. (2, 14)

Ver imagen joshlind3

The solution of the inequalities is required.

One of the solutions is [tex](5,10)[/tex]

Number of dimes is [tex]x[/tex]

Number of nickels is [tex]y[/tex]

Minimum number of coins is 15.

So, [tex]x+y\geq 15[/tex]

Maximum total value of the coins is $1

So, [tex]0.1x+0.05\leq 1[/tex]

The equations are

[tex]x+y=15[/tex]

[tex]0.1x+0.05y=1[/tex]

Points of the first equation

[tex](0,15)[/tex] and [tex](15,0)[/tex]

Graph the points and draw a line through them.

Points of the second equation

[tex]x=0[/tex]

[tex]y=\dfrac{1}{0.05}=20[/tex]

[tex]y=0[/tex]

[tex]x=\dfrac{1}{0.1}=10[/tex]

[tex](0,20)[/tex] and [tex](10,0)[/tex]

Graph the points and draw a line through them.

The shaded regions can be determined by substituting the point in the equations.

One of the solutions is [tex](5,10)[/tex]

This means there are 5 dimes and 10 nickels.

[tex]5+10=15\geq 15[/tex]

[tex]0.1\times 5+0.05\times 10=1\leq 1[/tex]

Hence, one of the solutions is [tex](5,10)[/tex].

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Ver imagen boffeemadrid