Joey built a model sailboat that is similar to his real sailboat. The triangular sail on
his real boat has a base of 25 feet. If the height of the sail on his model boat is 12
inches and the base is 15 inches, what is the height of the sail on his real boat?​

Respuesta :

Answer:

31.25

Step-by-step explanation:

25/12=2.083333

15 x 2.0833333=31.24999999995

round up to get 31.25

The height of the sail on his real boat is 20 feet.

We require the height of the sail on the real boat, H.

Let h be the height of sail on the model boat = 12 inches, B = base of sail on the real boat = 25 feet and b = base of sail on model boat = 15 inches.

By similar triangles,

H/h = B/b

H = Bh/b

Substituting the values of the variables into the equation, we have

H = Bh/b

H = 25 feet × 12 inches/15 inches

H = 25 feet × 4/5

H = 5 feet × 4

H = 20 feet

So, the height of the sail on his real boat is 20 feet.

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