please helpp mecwith this question
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[tex] \frac{1}{R} = \frac{1}{8} + \frac{1}{12} \\ [/tex]
[tex] \frac{1}{R} = \frac{1 \times 3}{8 \times 3} + \frac{1 \times 2}{12 \times 2} \\ [/tex]
[tex] \frac{1}{R} = \frac{3}{24} + \frac{2}{24} \\ [/tex]
[tex] \frac{1}{R} = \frac{3 + 2}{24} \\ [/tex]
[tex] \frac{1}{R} = \frac{5}{24} \\ [/tex]
Inverse both sides
[tex] \frac{R}{1} = \frac{24}{5} \\ [/tex]
[tex]R = \frac{24 \times 2}{5 \times 2} \\ [/tex]
[tex]R = \frac{48}{10} \\ [/tex]
[tex]R = 4.8 \: \: Ω[/tex]
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The correct answer is (( B )) .
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