Answer:
3.8 g Fe * 1 mol Fe/55.85 g Fe (molar mass) = .0680 mol Fe
.0680 mol Fe * 2 mol HBr/1 mol Fe (found in formula Fe+2HBr=>FeBr2+H2)=.136 mol HBr
.136 mol HBr*80.912 g HBr/1 mol HBr=11.004 g HBr (or 11 using 2 sig figs)
And the mass of H2 that is produced is 0.14 g
Explanation: