Respuesta :

Answer: If the air-plane travels 1020 km in one hour, then it will cover 4250 km in 25/6 hours.

The formula which relates distance, speed, and time is given by d = rt, where d is the distance traveled, r is the rate of travel or the speed, and t is the time traveled. To find out the distance an aircraft will travel in t = 25/6 hours, we must first find out the speed r of the aircraft in kilometers per hour (km/hr) as shown:

d = rt

1,020 km = r(1 hr)

(1,020 km)/(1 hr) = [r(1 hr.)]/(1 hr)

1,020 km/hr = r(1 hr./1 hr)

1,020 km/hr = r(1)

r = 1,020 km/hr

Now, calculating the distance the aircraft will travel in t = 25/6 hours, we have:

d = rt

= (1,020 km/hr)(25/6 hr)  

= (1,020)(25/6) km

= (1,020/6)(25) km

= (170)(25) km

= 4,250 km

Answer:

4250 km

Step-by-step explanation:

[tex]\Large\bf{GiveN,} \\ [/tex]

  • [tex] {Distance\:covered\: in \:1\:hour\:=\:1020\:km}[/tex]

  • [tex] {Distance\:covered\: in \:25/6\:hour\:= }[/tex] [tex] { 25/6\:×\:distance\:covered\: in \:1\:hour}[/tex]

⠀⠀⠀[tex] \textbf{Distance\:covered\: in \:1\:hour} [/tex]

⠀⠀⠀⠀⠀[tex] \implies [/tex][tex]\bf\dfrac{25}{6}[/tex] × 1020

⠀⠀⠀⠀⠀[tex] \implies [/tex][tex]\bf\dfrac{25×1020}{6×1}[/tex]

⠀⠀⠀⠀⠀[tex] \implies [/tex][tex]\bf\dfrac{25500}{6}[/tex]

⠀⠀⠀⠀⠀⠀ [tex]\small{\underline{\mathcal{\green{ =\:4250\:km}}}}[/tex]

[tex] \therefore[/tex][tex] {\:\:\:Distance\: covered\: in \:25/6\:hrs\:by\:plane}[/tex][tex] {⠀⠀⠀⠀⠀= 4250\:km}[/tex]