Answer:
Expressions C and D correctly determine the markup price.
Step-by-step explanation:
A markup in mathematics is when an object's price is raised by a certain percentage. Therefore, because we are told that the telescope is originally $400 and is marked up by 32%, we can actually mathematically evaluate this.
When you markup a price, you multiply the original price by [tex]1+x[/tex], where x is the percentage at which the object is marked up. However, x needs to be in decimal form for it to work out.
[tex]\frac{32}{100} = \small\boxed{0.32}[/tex]
Therefore, with this new decimal, we can add 1 to it.
[tex]1 + 0.32=\small\boxed{1.32}[/tex]
Finally, we multiply this result by the original price.
[tex]1.32 \times 400=\small\boxed{528}[/tex]
Therefore, we can already confirm that Expression C is one way to find the markup price.
- We can eliminate expression A because it did not use the formula [tex]1+x[/tex]. It only uses the decimal form of the percentage.
- We can eliminate expression B because the division to convert from the percentage form to the decimal form is flawed (the expression divided by 10 instead of 100) and also forgot to add 1 to the determined value.
Now, we can test the math for expressions D and E to see if either of these will equal $528.
Expression D is basically saying to add 32% of 400 to the original price. This would work out because we marked up the original price by 32%. Therefore, we can confirm that Expression D is also an expression that can be used to determine the markup price.
[tex]400 + 400(0.32)\\400(0.32) = 128\\400 + 128 = \small\boxed{528}[/tex]
Finally, we also need to check expression E. This expression is saying to add the already marked up price to 400. This would not be correct.
[tex]400 \times 400(1.32)\\400(1.32) = 528\\400 \times 528 = \small\boxed{\$ 211,200}[/tex]
Therefore, it has been determined that Expression C & Expression D are both equations that will find a markup price.
