Answer:
26
Step-by-step explanation:
First find the triangle of the base by using the Pythagorean theorem
[tex]\sqrt{24^2+6^2} = \sqrt{576+36} = \sqrt{612}[/tex]
So the diagonal of the base is the square root of 612
Now we can find the hypotenuse of GP using that and 8 in the Pythagorean theorem.
[tex]\sqrt{\sqrt{612}^2 + 8^2} = \sqrt{612+64} = \sqrt{676} = 26[/tex]
(Square root times itself is the number inside):
[tex]\sqrt{64} * \sqrt{64} = 64\\\sqrt{22} * \sqrt{22} = 22[/tex]
GP = 26
Hope this helps :)
