Respuesta :

helpmeoutplease71
So here is how we are going to prove that (2(tan x - cot x) / (tan^2 x - cot^2 x} = sin (2x). Follow it step by step:
LS = 2(tanx−cotx)
------------------
tan^2−cot^2x
= 2(tanx−cotx)
----------------------
(tanx−cotx)(tanx+cotx)
= 2
-------------------
(tanx+cotx)
= 2
-----------------
Sin2x+cos2x
---------------- sinxcosx
= 2
-------------
1
------------
sinxcosx
= 2sinxcosx
= sin2x
I hope that is the answer that you are looking for. Let me know if you need more help next time. Thanks for posting your question here in brainly!
noahaceja
Answer:

tan(2x)=tan(x+x)

tan(x+x)

tan(x)+tan(x)/1-tan(x)tan(x)

2tan(x)/1-tan(x)^2

tan(2x)

tan(2x)=tan(x+x) is True.

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