Respuesta :

It is fact that
6.023
×
10
23
formula units of barium nitrate have a mass of
16.6*10^23
⋅
g
. This is what we specify when we say molar mass. And thus the mass of
5.30
×
10
22
formula units of barium nitrate is the quotient multiplied by the molar mass:
5.30
×
10
22
6.023
×
10
23
m
o
l
×
16.6*10^23
⋅
g
⋅
m
o
l
−
1
samueladesida43

The mass of 16.6 × 10²³ molecules of barium nitrate is 718.7g

  • The number of moles of a substance can be calculated by dividing the mass by its molar mass. That is;

  • no. of moles = mass(g) ÷ molar mass (g/mol)

  • no. of moles of Ba(NO3)2 = 16.6 × 10²³ ÷ 6.02 × 10²³

  • no. of moles = 2.75 × 10⁰

  • no. of moles = 2.75moles.

  • Molar mass of Ba(NO3)2 = 261.34g/mol

  • mass of Ba(NO3)2 = 261.34 × 2.75

  • Mass of Ba(NO3)2 = 718.7g

  • Therefore, the mass of 16.6 × 10²³ molecules of barium nitrate is 718.7g.

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