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A golf ball is hit with an initial velocity of 80 ft/sec.Use the equation h(t)=80t-16t^2 where h(t) is the height of the object in feet and t is the time in seconds. How long will it take for the ball to hit the ground?

Respuesta :

Answer:

The ball takes 5 seconds to hit the ground

Step-by-step explanation:

The equation to model the height of a golf ball in time t is:

[tex]h(t)=80t-16t^2[/tex]

There are two moments when the height is zero: At launch time and when it hits the ground. To find the last time, we equate:

[tex]80t-16t^2=0[/tex]

Factoring out t:

[tex]t(80-16t)=0[/tex]

It gives us two solutions:

t=0

[tex]80-16t=0[/tex]

Solving:

[tex]-16t=-80[/tex]

[tex]t=-80/(-16)=5[/tex]

t = 5 sec

Thus, the ball takes 5 seconds to hit the ground