4x^2 - 9y^6
what patterns can be used ?
please and thank you !!!
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Answer:
B. (U+V)(U-V)
Step-by-step explanation:
Factoring
The given expression is:
[tex]4x^2-9y^6[/tex]
It should be noted that both terms are perfect squares:
[tex](2x)^2=4x^2[/tex]
[tex](3y^3)^2=9y^6[/tex]
Since it's a difference of squares, we need to use the following pattern to factor the required expression:
[tex](U^2-V^2)=(U+V)(U-V)[/tex]
Thus, the answer is
B. (U+V)(U-V)