Answer:
A quadratic equation for the height of an object is written as:
h(t) = a*t^2 + b*t + c
We can derivate it with respect to the time to get the velocity:
v(t) = 2*a*t + b
We can derivate it with respect to the time to get the acceleration:
a(t) = 2*a
Then:
a = half of the acceleration. (the gravitational acceleration for problems like this)
b = initial vertical velocity.
c = initial height.
In our case we have:
h(t) = -16t^2 + 44t + 3.5
-16 is half of the acceleration, we know that the gravitational acceleration is:
g = 32ft/s^2, and we have a negative sign because the gravity pullls the ball downwards.
44 is the initial vertical velocity of the ball (44ft/s)
3.5 is the initial height. (3.5ft)
Then the statement of Ivan is incorrect because the 16 does not represent the initial velocity