How would I unrationalize this fraction?
I am trying to find the cotangent in simplest form
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[tex] \cot(teetha) = - 1[/tex]
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The cotangent in simplest form is -1.
Trigonometry is mainly concerned with specific functions of angles and their application to calculations. Trigonometry deals with the study of the relationship between the sides of a triangle (right-angled triangle) and its angles.
For the given situation,
cos θ = √2 / 2
We know that from trigonometric ratio,
[tex]cos \theta = \frac{Adjacent}{Hypotenuse}[/tex] , [tex]cot \theta = \frac{Adjacent }{ Opposite }[/tex]
So, the adjacent side = √2 and the hypotenuse side = 2.
The other side of the right triangle can be found by Pythagoras theorem,
[tex]hypotenuse^{2}=adjacent^{2}+opposite^{2}[/tex]
⇒ [tex]2^{2}=(\sqrt{2} )^{2} +opposite^{2}[/tex]
⇒ [tex]opposite^{2} = 4-2[/tex]
⇒ [tex]opposite = \sqrt{2}[/tex]
Thus, [tex]cot \theta = \frac{\sqrt{2} }{\sqrt{2} }[/tex]
⇒ [tex]cot \theta = 1[/tex]
Since cot θ < 0, [tex]cot \theta = - 1[/tex]
Hence we can conclude that the cotangent in simplest form is -1.
Learn more about trigonometry here
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