Respuesta :
Answer:
0.102 M.
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 5 mL
Molarity of stock solution (M1) = 5.103 M
Volume of diluted solution (V2) = 250 mL
Molarity of diluted solution (V2) =?
The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:
M1V1 = M2V2
5.103 × 5 = M2 × 250
25.515 = M2 × 250
Divide both side by 250
M2 = 25.515 / 250
M2 = 0.102 M
Thus, the molarity of the diluted solution is 0.102 M.
The dilution of the NaOH results in the dilution of the molarity of the solution. The molarity of the final NaOH solution is 0.102 M.
What is molarity?
Molarity is the concentration unit that defines the amount of solute present in a liter of solution.
The dilution of the solution results in a change in the molarity. It can be accessed as:
[tex]\rm M_1V_1=M_2V_2[/tex]
The initial molarity of the solution is, [tex]\rm M_1=5.103\;M[/tex]
The initial volume of the NaOH is, [tex]\rm V_1=5\;mL[/tex]
The final volume of the NaOH is, [tex]\rm V_2=250\;mL[/tex]
Substituting the values for the calculation of final molarity, [tex]\rm M_2[/tex]:
[tex]\rm 5.103\;\M\;\times\;5.0\;mL=M_2\;\times\;250\;mL\\\\M_2=\dfrac{5.103\;\M\;\times\;5.0\;mL}{250\;mL} \\\\M_2=0.102\;M[/tex]
The molarity of the NaOH solution after dilution is 0.102 M.
Learn more about molarity, here:
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