You are using 1000 feet of fence to create a rectangular enclosure. Let X represents length of the rectangle. Please use proper unit in each answer. A rectangle drawing could help. 1. Express the width of the rectangle in terms of the length X. 2. Express the surface area of the rectangle in terms of X. 3. What value of X gives the maximum surface area. 4. What is the maximum surface area?

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Answer:

1. Express the width of the rectangle in terms of the length X.

width = 500 - X

2. Express the surface area of the rectangle in terms of X.

area = -X² + 500X

3. What value of X gives the maximum surface area?

maximum surface area results from the rectangle being a square, so 1,000 ÷ 4 = 250

X = 250 ft

4. What is the maximum surface area?

maximum surface area = X² = 250² = 62,500 ft²

Step-by-step explanation:

since the perimeter = 1,000

1,000 = 2X + 2W

500 = X + W

W = 500 - X

area = X · W = X · (500 - X) = 500X - X² or -X² + 500X

The area of a shape is the amount of space it occupies.

  • The width in terms of x is 500 - x
  • The surface area in terms of x is x(500 - x)
  • The value of x that gives maximum surface area is 250 feet
  • The maximum area is 62500 square feet

The length is represented as x.

Let the width be y.

So, we have:

[tex]\mathbf{Perimeter =2(x + y)}[/tex]

This gives

[tex]\mathbf{2(x + y) = 1000}[/tex]

Divide both sides by 2

[tex]\mathbf{x + y = 500}[/tex]

Make y the subject

[tex]\mathbf{y = 500 -x}[/tex]

So, the width in terms of x is 500 - x

The surface area is calculated as:

[tex]\mathbf{A = xy}[/tex]

Substitute [tex]\mathbf{y = 500 -x}[/tex]

[tex]\mathbf{A = x(500 - x)}[/tex]

So, the surface area in terms of x is x(500 - x)

Expand [tex]\mathbf{A = x(500 - x)}[/tex]

[tex]\mathbf{A = 500x - x^2}[/tex]

Differentiate

[tex]\mathbf{A' = 500- 2x}[/tex]

Equate to 0

[tex]\mathbf{500- 2x = 0}[/tex]

Rewrite as:

[tex]\mathbf{2x = 500}[/tex]

Divide both sides by 2

[tex]\mathbf{x = 250}[/tex]

So, the value of x that gives maximum surface area is 250

Substitute 250 for x in [tex]\mathbf{A = x(500 - x)}[/tex]

[tex]\mathbf{A = 250 \times (500 - 250)}[/tex]

[tex]\mathbf{A = 250 \times 250}[/tex]

[tex]\mathbf{A = 62500}[/tex]

Hence, the maximum area is 62500

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