Answer:
(A) 165
(B) 330
Step-by-step explanation:
Total number of students in the class = 11
(A) How many different combinations of 3 selected students can he create?
ⁿCₓ = n! ÷ [(n - x)! x!]
n = 11, x = 3
11! / [8! 3!] = 165
HINT: 8! or 8 factorial represents [8x7x6x5x4x3x2x1]
(B) How many different combinations of 4 selected students can he create?
ⁿCₓ = n! ÷ [(n - x)! x!]
n = 11, x = 4
11! / [7! 4!] = 330
Same hint applies here, for all numbers with the factorial sign.