Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving
upwards and is slowing down at a rate of 2.0 m/s? What is Abdul's apparent weight?
Use g = 10 m/s

Respuesta :

Answer:

Abdul has an apparent weight of 600 newtons.

Explanation:

The statement is incorrectly written. Its correct form is:

Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving upwards and is slowing down at a rate of 2.0 m/s2. What is Abdul's apparent weight? Use g = 10 m/s2.

According to the statement, we know that elevator and Abdul himself are moving upwards and decelerating, which means that Abdul feels a force from elevator is the same direction of his weight. From 2nd Newton's Law we find the following equation of equilibrium:

[tex]\Sigma F = F-m\cdot g = m\cdot a[/tex] (1)

Where:

[tex]F[/tex] - Apparent weight, measured in newtons.

[tex]m[/tex] - Mass of Abdul, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the elevator-Abdul system, measured in meters per square second.

In (1) we clear the apparent weight:

[tex]F = m \cdot (a+g)[/tex]

If we know that [tex]m = 50\,kg[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]g = 10\,\frac{m}{s^{2}}[/tex], we find that the apparent weight of Abdul is:

[tex]F = (50\,kg)\cdot \left(2\,\frac{m}{s^{2}}+10\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 600\,N[/tex]

Abdul has an apparent weight of 600 newtons.