Does anyone know this?
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Answer:
B
Step-by-step explanation:
Given
g(x) = 2x² - 6x - 56 ← factor out 2 from each term
= 2(x² - 3x - 28) ← factor the quadratic
Consider the factors of the constant term (- 28) which sum to give the coefficient of the x- term (- 3)
The factors are + 4 and - 7, since
4 × - 7 = - 28 and 4 - 7 = - 3 , thus
x² - 3x - 28 = (x + 4)(x - 7) , then
g(x) = 2x² - 6x - 56 = 2(x + 4)(x - 7) → B