We are given:
P1 = 1 atm P2 = 3 atm
T1 = 300 K T2 = 600 K
V1 = 6 L V2 = v L
Finding the final Volume:
From the ideal gas equation:
PV = nRT
since in the given scenario, the universal gas constant (R) and number of moles(n) are constant
So, for both the cases, the value of n*R will be a constant k
Hence, we can write that:
PV / T = k [where k is a constant]
Since the constant 'k' is the same for both the cases, we can write that:
P1V1 / T1 = P2V2 / T2
replacing the variables
1 * 6 / 300 = 3 * v / 600
1/50 = v / 200
v = 200/50
v = 4 L
Therefore, the volume of the gas at 600K and 3 atm will have a volume of 4 L
