Respuesta :

Space

Answer:

[tex]V = 0.117 \ L[/tex]

General Formulas and Concepts:

Chem

  • Reading a Periodic Table
  • Writing compounds and polyatomic ions
  • Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

1.57 M KOH (potassium hydroxide)

10.3 g KOH

Step 2: Define conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of KOH - 39.10 + 16.00 + 1.01 = 56.11 g/mol

Step 3: Convert

[tex]10.3 \ g \ KOH(\frac{1 \ mol \ KOH}{56.11 \ g \ KOH} )[/tex] = 0.183568 mol KOH

Step 4: Solve for Volume

  1. Substitute:                    [tex]1.57 \ M=\frac{0.183568 \ mol}{x \ L}[/tex]
  2. Move x:                         [tex]x1.57 \ M=0.183568 \ mol[/tex]
  3. Isolate x:                       [tex]x=\frac{0.183568 \ mol}{1.57 \ M}[/tex]
  4. Evaluate:                      [tex]x=0.116922 \ L[/tex]

Step 5: Check

We are given 3 sig figs. Follow sig fig rules.

[tex]0.116922 \ L \approx 0.117 \ L[/tex]

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