If 175 grams of lead (ll) iodide is produced from the reaction, how many moles of potassium nitrate are produced?

Equation: 2KI + Pb(NO₃)₂ = 2KNO₃ + Pbl₂

Respuesta :

Moles of potassium nitrate produced : 0.76

Further explanation

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

2KI + Pb(NO₃)₂ ⇒ 2KNO₃ + Pbl₂

MW KNO₃ : 101.1032 g/mol

MW Pbl₂ = 461,01 g/mol

175 grams of Pbl₂ , mol :

[tex]\tt mol=\dfrac{175}{461.01}=0.38[/tex]

mol ratio KNO₃ : Pbl₂ = 2 : 1, so mol KNO₃ = 0.38 x 2 = 0.76

Mass of KNO₃ :

[tex]\tt mass=0.76\times 101.1032=76.838~g[/tex]