Answer:
[tex]a = p*q\\b = (p*s)+(q*r)\\c = r*s[/tex]
Step-by-step explanation:
The standard form of trinomial is given as:
[tex]ax^2+bx+c[/tex]
And the factored form is:
[tex](px+r)(qx+s)[/tex]
In order to find the values of a,b and c in terms of p,q,r and s we will take the factored form, multiply it and then compare it with the standard form.
So,
[tex](px+r)(qx+s)\\=px(qx+s)+r(qx+s)\\= pqx^2+psx+qrx+rs\\= pqx^2+(ps+qr)x+rs[/tex]
Now comparing it with the standard form of trinomial
We will compare the co-efficients of x^2, x and the constant
By comparing, we get
[tex]a = pq = p*q\\b = ps+qr = (p*s)+(q*r)\\c = rs = r*s[/tex]
Hence,
[tex]a = p*q\\b = (p*s)+(q*r)\\c = r*s[/tex]
