leah3850
contestada

A 7.0 liter balloon at room temperature contains helium gas. if the temperature is halved, what happen to the volume?​

Respuesta :

The volume = 6.71 L

Further explanation

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

V₁=7 L

T₁=25 °C(room temperature) + 273 = 298 K

T₂=12.5(halved) + 273 = 285.5 K

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\\dfrac{7}{298}=\dfrac{V_2}{285.5}\\\\V_2=6.71~L[/tex]