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Faith invested \$1,100 in an account paying an interest rate of 5.1\% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 18 years?

Respuesta :

Compounded Continuously:

A=Pe^{rt}

A=Pe

rt

P=1100\hspace{35px}r=0.051\hspace{35px}t=18

P=1100r=0.051t=18

Given values

A=1100e^{0.051(18)}

A=1100e

0.051(18)

Answer: 2,750

Explanation:

Plug in

A=1100e^{0.918}

A=1100e

0.918

Multiply

A=2754.70450683

A=2754.70450683

Use calculator (with e button)

A\approx 2750

A≈2750

Round to nearest ten dollars

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