Respuesta :
Answer/Step-by-step Explanation:
To determine if segment AB and CD are parallel, perpendicular, or neither, calculate the slope of each.
✍️If the slope of AB and CD are the same value, then they are parallel.✅
✍️If the slope of one is the negative reciprocal of the other, then they are perpendicular.☑️
✍️If their slopes are different, or the slope of one is not the negative reciprocal of the other, then they are neither.❌
1. AB formed by (-2, 13) and (0, 3)
CD formed by (-5, 0) and (10, 3)
Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 13}{0 -(-2)} = \frac{-10}{2} = -5 [/tex]
Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 0}{10 -(-5)} = \frac{3}{15} = \frac{1}{5} [/tex].
☑️-5 is the negative reciprocal of ⅕, therefore segments AB and CD are perpendicular
2. AB formed by (3, 7) and (-6, 1)
CD formed by (-6, -5) and (0, -1)
Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 7}{-6 - 3} = \frac{-6}{-9} = \frac{2}{3} [/tex]
Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 -(-5)}{0 -(-6)} = \frac{4}{6} = \frac{2}{3} [/tex].
✅Segment AB and CD have the same slope value of ⅔. Therefore, they are parallel.
3. AB formed by (-6, 2) and (-2, 4)
CD formed by (-1, 11) and (5, -7)
Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - 2}{-2 -(-6)} = \frac{2}{4} = \frac{1}{2} [/tex]
Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{-7 - 11}{5 -(-1)} = \frac{-18}{6} = -3 [/tex].
❌The slopes of Segments AB and CD are not the same (½ and -3). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.
4. AB formed by (-3, 8) and (2, 3)
CD formed by (-4, 6) and (-8, 2)
Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 8}{2 -(-3)} = \frac{-5}{5} = -1 [/tex]
Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 6}{-8 -(-4)} = \frac{-4}{-4} = 1 [/tex].
❌The slopes of Segments AB and CD are not the same (1 and -1). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.
5. AB formed by (-8, -1) and (-4, 2)
CD formed by (0, -3) and (12, 6)
Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 -(-1)}{-4 -(-8)} = \frac{3}{4} [/tex]
Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 -(-3)}{12 - 0} = \frac{9}{12} = \frac{3}{4} [/tex].
✅Segment AB and CD have the same slope value of ¾. Therefore, they are parallel.
6. AB formed by (6, 5) and (3, -1)
CD formed by (2, -5) and (-4, 7)
Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 5}{3 - 6} = \frac{-6}{-3} = 2 [/tex]
Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 -(-5)}{-4 - 2} = \frac{12}{-6} = -2 [/tex].
❌The slopes of Segments AB and CD are not the same (2 and -2). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.
To determine if the given equations are parallel, perpendicular, or neither, ensure both equations are in the slope-intercept form, y = mx + b, where m is the slope.
7. 3x + 2y = 6 and y = -³/2x + 5
Rewrite the first equation in slope-intercept form
3x + 2y = 6
2y = -3x + 6
y = -3x/2 + 6/2
y = -³/2x + 3
The slope of the first equation is -³/2.
The slope of the second equation is -³/2.
✅Both equations have the same slope value of -³/2. Therefore, they are parallel.
8. 3y = 4x + 15 and 9x + 12y = 12
Rewrite both equations in slope-intercept form.
3y = 4x + 15
y = 4x/3 + 15/3
y = ⁴/3x + 5
And
9x + 12y = 12
12y = -9x + 12
y = -9x/12 + 12/12
y = -¾x + 1
The slope of the first equation is ⁴/3.
The slope of the second equation is -¾..
☑️-¾ is the negative reciprocal of ⁴/3. Therefore both AB equations are perpendicular.
9. 8x - 2y = 4 and x + 4y = -12
Rewrite both equations in slope-intercept form.
8x - 2y = 4
-2y = -8x + 4
y = -8x/-2 + 4/-2
y = 4x - 2
And
x + 4y = -12
4y = -x - 12
y = -x/4 - 12/4
y = -¼x - 3
The slope of the first equation is 4.
The slope of the second equation is -¼..
☑️-¼ is the negative reciprocal of 4. Therefore both AB equations are perpendicular.
10. 3x + 2y = 10 and 2x + 3y = -3
Rewrite both equations in slope-intercept form.
3x + 2y = 10
2y = -3x + 10
y = -3x/2 + 10/2
y = -³/2x + 5
And
2x + 3y = -3
3y = -2x - 3
y = -⅔x - 1
The slope of the first equation is -³/2.
The slope of the second equation is -⅔.
❌The slopes of the first equation and second equation are not the same (-³/2 and -⅔). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.
11. -4y = -2x + 8 and 3x - 6y = 6
Rewrite both equations in slope-intercept form.
-4y = -2x + 8
y = -2x/-4 + 8/-4
y = ½x - 2
And
3x - 6y = 6
-6y = -3x + 6
y = -3x/-6 + 6/-6
y = ½x - 1
The slope of the first equation is ½.
The slope of the second equation is ½.
✅Both equations have the same slope value of ½. Therefore, they are parallel.
12. y = 8 and x = -1
The first equation is a horizontal line. The slope of am horizontal line is always zero.
The second equation is a vertical line. The slope of a vertical line is undefined.
❌Therefore, they are neither parallel nor perpendicular.
