Answer:
Area = (6π + 10)[tex]m^{2}[/tex]
Step-by-step explanation:
One way to solve this is to get the area of the big circle and subtract the small inner circle and divide by 2; also add the area of the rectangle (LxW)
Area = (big circle - small circle)/2 + area of rectangle
Big circle: radius = (4/2 + 2) = 4
Area of big circle = π[tex]r^{2}[/tex] = [tex]4^{2}[/tex]π = 16π
Small circle: radius = (4/2) = 2
Area of small circle = π[tex]r^{2}[/tex] = [tex]2^{2}[/tex]π = 4π
Rectangle
Length L =5 and Width W= 2
Area of rectangle = LxW = 5*2 = 10
Area = (big circle - small circle)/2 + area of rectangle
Area = (16π - 4π)/2 + 10
Area = (12π)/2 + 10
Area = (6π + 10)[tex]m^{2}[/tex]
