Answer:
The brace is [tex]2\sqrt{41}[/tex] ft ≅ 12.806 ft long
Step-by-step explanation:
The length of the diagonal of a rectangle can be found using this rule
[tex]d=\sqrt{l^{2}+w^{2}}[/tex] , where
∵ The gate has shaped a rectangle
∵ Its length = 10 ft
∵ Its width = 8 ft
∴ l = 10 and w = 8
∵ The brace is the diagonal
→ By using the rule above
∴ [tex]d=\sqrt{(10)^{2}+(8)^{2}}=\sqrt{100+64}=\sqrt{164}[/tex]
∴ The length of the brace = [tex]2\sqrt{41}[/tex] ≅ 12.806 ft
∴ The brace is [tex]2\sqrt{41}[/tex] ≅ 12.806 ft long
