Respuesta :
Answer: The bag of candy corn will take 5 seconds to land on the floor and it will hit it with velocity of 49m/s.
Step-by-step explanation: A free falling object has only Gravitational Force acting on it, so acceleration will be due to gravity, which has magnitude
g = 9.8m/s².
As Professor Sosa drops the bag, its initial velocity and time are 0.
The building has a height of 400ft, so adjusting units: y = 121.92 m and [tex]y_{0}[/tex] = 0.
For this problem, going down will be the positive reference.
Then:
[tex]y=y_{0}+v_{0}t+\frac{g}{2}t^{2}[/tex]
[tex]\Delta y=v_{0}t+\frac{g}{2}t^{2}[/tex]
[tex]121.92=\frac{9.8}{2}t^{2}[/tex]
[tex]t=\sqrt{\frac{121.92*2}{9.8} }[/tex]
t ≈ 5
It will take 5s for the candy corn bag to land on the ground.
Acceleration is the change in velocity per change in time, so:
[tex]g=\frac{\Delta v}{\Delta t}[/tex]
As initial velocity and time are 0 and rearraging it:
v = g.t
v = 9.8*5
v = 49
The bag will hit the ground with velocity of magnitude 49 m/s.
