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An imaginary element (Atomic weight 93.7140) has three naturally-occurring isotopes with isotopic weights of 92.9469, 93.2923 and 94.9030. The abundance of the lightest isotope is 42.38 %. What is the percentage abundance of the heaviest isotope?

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Answer:

Explanation:=∑×100isotope)ofAAbundance(%r=78.710.1311.1723.98524.98625.983100100100⎛⎞⎛⎞⎛⎞×+×+×⎜⎟⎜⎟⎜⎟⎝⎠⎝⎠⎝⎠= 18.876 + 2.5311 + 2.902 = 24.309∑×100isotope)ofAAbundance(%r,∑= sum ofExample 1

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