a. {[(-15+5)×2+8]-32÷8}-(-7)

b. (5-2)³×2+[-4+(-7)]÷(-2+4)²

c. {-10-[12+(-3)²] + 3³}+3³}÷(-3)

I'll mark you brainliest if you solve these with explanation​

Respuesta :

Answer:

Step-by-step explanation:

The answers are:

A)  {[(-15+5)×2+8]-32÷8}-(-7)

Calculate within parentheses: -16 - (-7)

Add and subtract (left to right): -16 - (-7) = -9

B) (5-2)³×2+[-4+(-7)]÷(-2+4)²

To solve this problem, you need to follow the steps of order of operations.

Calculate within parentheses: [tex]3^{3}[/tex] * 2 + [-4 + (-7)] ÷ (-2+4)²

Calculate within parentheses: [tex]3^{3}[/tex] *2 -11 ÷ (-2+4)²

Calculate within parentheses: 27 × 2 - 11 ÷ (-2+4)²

Calculate exponents: 27 × 2 -11 ÷ 4

Multiply and divide: 54 - 11 ÷ 4

Multiply and divide: 54 - [tex]\frac{11}{4}[/tex]

Add and Subtract:  [tex]\frac{205}{4}[/tex]

Convert improper fractions to mixed numbers: [tex]\frac{205}{4}[/tex] = [tex]51\frac{1}{4}[/tex]

C) {-10-[12+(-3)²] + 3³}+3³}÷(-3)

Calculate within parentheses: -4 ÷ (-3)

Multiply and divide:  [tex]\frac{-4}{(-3)}[/tex]

Simplify and convert improper fraction to a mixed number:

[tex]\frac{-4}{(-3)}[/tex] = [tex]\frac{4}{3}[/tex] = [tex]1\frac{1}{3}[/tex]

Hope this helped! If so, please mark brainliest.