Answer:
The temperature of the Nitrogen after throttling is [tex]T_2 = 300 \ K[/tex]
Explanation:
From the question we are told that
The temperature is [tex]T_1 = 300 \ K[/tex]
The pressure is [tex]P = 200 \ kPa = 200 * 10^{3} \ Pa[/tex]
The pressure after being [tex]P_1 = 100 \ kPa = 100 * 10^{3} \ Pa[/tex]
Generally from the first law of thermodynamics we have that
[tex]Q - W = \Delta U + \Delta K[/tex]
Here [tex]\Delta U[/tex] is the change internal energy which is mathematically represented as
[tex]\Delta U = C_p (T_2 - T_1)[/tex]
Here [tex]C_p[/tex] is the specific heat of the gas at constant pressure
[tex]\Delta K[/tex] is the change kinetic energy which is negligible
Q is the thermal energy which is Zero for an adiabatic process
W is the work done and the value is zero given that the gas was throttled adiabatically
So
[tex]0= \Delta U +0[/tex]
=> [tex]\Delta U = 0[/tex]
=> [tex](T_2 - 300) = 0[/tex]
=> [tex]T_2 = 300 \ K[/tex]
