Respuesta :
Answer:
54 s
Explanation:
Given that,
Mass of a car, m = 15000 kg
Initial speed, u = 5.4 m/s
Final speed, v = 0 (it comes to rest)
Force, F = 1500 N
We need to find time when it comes to rest. Let it is t. Net force is given by :
F = ma, a is acceleration of the car
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{15000\times (0-5.4)}{1500}\\\\t=54\ s[/tex]
So, it will take 54 seconds to come to rest.
The time required to bring the car to rest is 54 s and the right option is (b) 54 s.
To calculate the time required for the force to bring the car to rest, we use the formula below.
Formula:
- F = m(v-u)/t............ Equation 1
Where:
- F = Force applied to the car
- m = mass of the car
- v = final velocity of the car
- u = initial velocity of the car
- t = time.
Make t the subject of the equation
- t = m(v-u)/F............. Equation 2
From the question,
Given:
- F = -1500 N (stopping force)
- m = 15000 kg
- v = 0 m/s (to rest)
- u = 5.4 m/s
Substitute these values into equation 2
- t = [1500(0-5.4)]/-1500
- t = -81000/-1500
- t = 54 seconds
- t ≈ 54 s
Hence, The time required to bring the car to rest is 54 s and the right option is (b) 54 s.
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