Answer:
[tex]Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(l)[/tex]
Explanation:
Hello!
In this case, when writing chemical reactions from the given names we must make sure we know the proper formula for each reacted and produced species; thus, since solid iron (III) oxide is [tex]Fe_2O_3[/tex], hydrogen gas is [tex]H_2[/tex], solid iron is Fe and liquid water is just [tex]H_2O[/tex], we can write:
[tex]Fe_2O_3(s)+H_2(g)\rightarrow Fe(s)+H_2O(l)[/tex]
However, since different amount of atoms of iron, hydrogen and oxygen are present at each side of the equation, we balance it by adding the following coefficients to each molecule:
[tex]Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(l)[/tex]
And now it is balanced with two iron atoms, three oxygen atoms and six hydrogen atoms at both reactants and products.
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