Answer:
The value is [tex]b = 0.00026 \ kg / m[/tex]
Explanation:
From the question we are told that
The mass of the Ping-Pong is [tex]m = 2.3 \ g = 0.0023 \ kg[/tex]
The terminal speed is [tex]v = 9.3 \ m/s[/tex]
The drag force is [tex]bv^2[/tex]
Generally the resultant force on the Ping- Pong is mathematically represented as
[tex]F = mg - bv^2[/tex]
when terminal velocity is attained , the resultant force is zero so
[tex]0 = mg - bv^2[/tex]
=> [tex]b = \frac{m * g}{v^2}[/tex]
=> [tex]b = \frac{0.0023 * 9.8}{ 9.3 ^2}[/tex]
=> [tex]b = 0.00026 \ kg / m[/tex]
