Answer:
[tex]p(x)=x^3-7x-6 = (x+1)(x+2)(x-3)[/tex]
Step-by-step explanation:
Given that polynomial:
[tex]p(x)=x^3-7x-6[/tex]
Known factor: [tex](x+1)[/tex]
To find:
Equation of the polynomial as the product of linear factors.
Solution:
The degree of polynomial is 3, and when we divide it by a linear equation, the result will be a quadratic. That quadratic will have 2 solutions.
We can solve the quadratic in two linear factors and as a result we will have the answer.
First of all, we need to divide the polynomial [tex]p(x)[/tex] with the given factor [tex](x+1)[/tex] to find the other factors.
[tex]\dfrac{x^3-7x-6}{x+1} = x^2-x-6[/tex]
Solving the quadratic:
[tex]x^2-x-6 = x^2-3x+2x-6\\\Rightarrow x(x-3)+2(x-3)\\\Rightarrow (x+2)(x-3)[/tex]
So, the answer is:
[tex]p(x)=x^3-7x-6 = (x+1)(x+2)(x-3)[/tex]
