A certain bacteria multiply exponentially at a rate of 8% per day. If 2 bacteria exist initially, how many
will be present after 25 days?

Respuesta :

Answer:

After 25 days will be present about 13.70 ≅ 13 bacteria

Step-by-step explanation:

The form of the exponential function is y = a [tex](1+r)^{x}[/tex] , where

  • a is the initial value
  • r is the rate in decimal

∵ A certain bacteria multiply exponentially at a rate of 8% per day

→ Assume that y is the number of bacteria, x is the number of days

r = 8% = [tex]\frac{8}{100}[/tex] = 0.08

∵ 2 bacteria exist initially

a = 2

→ Substitute them in the form of the equation above

∵ y = 2 [tex](1+0.08)^{x}[/tex]

y = 2 [tex](1.08)^{x}[/tex]

x = 25

→ Substitute x in the equation by 25

∴ y = 2 [tex](1.08)^{25}[/tex]

y = 13.69695

After 25 days will be present about 13.70 bacteria

Note: The number of bacteria must be the whole number so the answer should be 13 bacteria will be present after 25 days.