The statement describes the equivalent vector is A) The magnitudes are 10, and the direction angles are about 18º.
How to find the cross product of two vectors?
Suppose that two vectors in consideration are u and v, then their cross product is evaluated as:
[tex]u \times v = |u|.|v|.sin(\theta)\hat{n}[/tex]
where
the normal unit vector whose direction is decided by right hand thumb rule, and theta is the angle between u and v vector.
The two bars around a vector represents the magnitude of that vector.
Cross product returns the result as a vector itself.
From the given graph we can conclude that the magnitudes are 10, and the direction angles are about 18º.
The statement describes the equivalent vector is A) The magnitudes are 10, and the direction angles are about 18º.
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