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In a chemistry class, Gabby prepared a solution by mixing 25 grams (g) of sugar in 80g of water. What are the concentration of the solute and solvent in percent (%) by mass?

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boffeemadrid

Answer:

Solute concentration is 23.81% and solvent concentration is 76.19%.

Explanation:

Solute = 25 g of sugar

Solvent = 80 g of water

Solute concentration

[tex]\dfrac{\text{Solute}}{\text{Solute+Solvent}}\times 100=\dfrac{25}{25+80}\\ =23.81\%[/tex]

Solvent concentration

[tex]\dfrac{\text{Solvent}}{\text{Solute+Solvent}}\times 100=\dfrac{80}{25+80}\\ =76.19\%[/tex]

The solute concentration is 23.81% and solvent concentration is 76.19%.

It can be stated in terms of mass percent, with the mass of the solute per unit mass (Kg or g) of the mixture as the unit of concentration. Water and sugar are used in this mixture.

[tex]\text{Solute = 25 g of sugar}\\\\\text{Solvent} = \text{80 g of water}[/tex]

[tex]\text{Computation of the Solute concentration}[/tex]

[tex]= \text{Solute}/\text{Solute + Solvent}[/tex] × [tex]100[/tex]

[tex]= 25/25+80[/tex]

[tex]=23.81[/tex]%

[tex]\text{Computation of the Solvent concentration}[/tex]

[tex]= \text{Solvent}/\text{Solvent+ Solute}[/tex] ×[tex]100[/tex]

[tex]= 80/80+25[/tex]

[tex]=76.19[/tex]%

For more information related to the computation of the solvent and solute percentage, refer to the link:

https://brainly.com/question/15089293?referrer=searchResults

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