With the use of K.E formula, the correct answers are:
a.) At point B, velocity = 2m/s
b.) At point C, velocity = 4m/s
C.) At point D, velocity = 3.5 m/s
POTENTION ENERGY
At maximum energy, total energy will be equal to maximum kinetic energy.
Given that a 2.5 kg mass starts from rest at point A and moves along the x-axis subject to the potential energy shown in the given figure.
Let us assume the that their maximum potential energies are given.
Total energy = maximum P.E = Maximum K.E
According to the graph, the P.E at point B,C, and D are:
- Point B = 5J, distance = 4m
- Point C = 20J, distance = 6m
- Point D = 15J, distance = 15m
Since Maximum P.E = Maximum K.E = 1/2m[tex]v^{2}[/tex]
At point B
5 = 1/2 x 2.5 x [tex]v^{2}[/tex]
[tex]v^{2}[/tex] = 10/2.5
[tex]v^{2}[/tex] = 4
v = [tex]\sqrt{4}[/tex]
v = 2 m/s
At point C
20 = 1/2 x 2.5 x [tex]v^{2}[/tex]
[tex]v^{2}[/tex] = 40/2.5
[tex]v^{2}[/tex] = 16
v = [tex]\sqrt{16}[/tex]
v = 4 m/s
At point D
15 = 1/2 x 2.5 x [tex]v^{2}[/tex]
[tex]v^{2}[/tex] = 30/2.5
[tex]v^{2}[/tex] = 12
v = [tex]\sqrt{12}[/tex]
v = 3.5 m/s
b.) The turning point should be any point where velocity is negative. Since there is no point where velocity is negative, let us consider the points where potential energy is increasing.
The turning points of the mass will be at point B and D
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