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A sample of gas occupies a volume of 7.50 L at 28.0C. At what temperature is the volume of the gas 4.00 L if the pressure is kept constant.

Respuesta :

nat332529

Answer:

Explanation:

To solve this, you must use Charles' Law:

V1/T1 = V2/T2

The values given are:

V1 = 7.50 L

V2 = 4.00 L

Temperature must be in Kelvin

Conversion: 28+273 = 301 K

Substitute values in Charles' Law:

7.50L /301 K = 4.00/T2

Cross-Multiply:

(7.50)(T2) = 1204

Solve for T2:

T2 = 160.53 K or -112.47˚C

This makes sense, as volume and temperature are directly proportional. As V increases, so will T and vice versa.

nuhulawal20

Provided that the pressure is kept constant, if the volume of the gas is decreased to the given value, its temperature also decreases to -113.15°C.

What is Charle's law?

Charle's law states that the volume of an ideal gas is directly proportional to the absolute temperature provided pressure is kept at constant.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 7.50L
  • Initial temperature T₁ = 28°C = 301.15K
  • Final volume V₂ = 4.00L
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

V₁/T₁ = V₂/T₂

V₁T₂ = V₂T₁

T₂ = V₂T₁ / V₁

T₂ = 4.00L × 301.15K / 7.50L

T₂ = 1204.6LK / 7.50L

T₂ = 160.6K

T₂ = -113.15°C

Provided that the pressure is kept constant, if the volume of the gas is decreased to the given value, its temperature also decreases to -113.15°C.

Learn more about Charle's law here: brainly.com/question/21184611

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