Respuesta :
[tex]p(x)=5x^{3} +8x^{2} -3x+1\\\\p(-2) =5(-2^{3}) + 8(-2^{2}) - 3(-2) + 1\\\\p(-2) = 5(-8) + 8(4) + 6 + 1\\\\p(-2) = -40 + 32 + 7\\\\p(-2) = -1[/tex]
hope that this helps! :)
The value of the function [tex]p(x) = 5x^3 + 8x^2 - 3x + 1[/tex] at [tex]x=-2[/tex] is [tex]-1[/tex].
To find the value of a function [tex]p(x)[/tex] at [tex]x=a[/tex], put [tex]a[/tex] in all the places of [tex]x[/tex] in the function.
Here, [tex]p(x)=5x^3+8x^2-3x+1.[/tex]
At [tex]x=-2[/tex]
[tex]p(-2)=5(-2)^3+8(-2)^2-3(-2)+1.[/tex]
[tex]p(-2)=5(-8)+8(4)-3(-2)+1.[/tex]
[tex]p(-2)=-40+32+6+1.[/tex]
[tex]p(-2)=-40+32+6+1.[/tex]
[tex]p(-2)=-40+39.[/tex]
[tex]p(-2) = -1.[/tex]
So, the value of the function at [tex]x=-2[/tex] is [tex]-1[/tex].
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