Answer:
5280people
Step-by-step explanation:
Given parameters:
Percentage increase of population = 25%
Population now = 6600
Unknown:
Population last year = ?
Solution:
Let the population last year = y;
Then;
Percentage of last years population plus the population of last year should give us this year's population;
([tex]\frac{25}{100}[/tex] of y) + y = 6600
0.25y + y = 6600
1.25y = 6600
y = [tex]\frac{6600}{1.25}[/tex] = 5280people
Last year, there was 5280people in the locality.
The population of the last year is 5280.
Given that,
The population of boom towns has increased by 25%.
The population is now 6,600.
We have to determine,
What was the population last year?
According to the question,
Let, the population of the last year is x,
The population of boom towns has increased by 25%.
The population is now 6,600.
Then,
The population of the last year is,
[tex]\dfrac{25}{100} x+ x = 6600\\\\ 0.25x + x= 6600\\\\ 1.25 x = 6600\\\\x= \dfrac{6600}{1.25}\\\\x= 5,280[/tex]
Hence, The required population of the last year is 5280.
To know more about Percentages click the link given below.
https://brainly.com/question/2155156
