Three blocks are sliding together to the right along a surface of negligible friction when a force with magnitude Fext is exerted to the left on the rightmost block, as shown in the figure. The masses of the blocks are indicated in the figure. If the force is exerted for a time Δt , what is the change in velocity of the center of mass of the three-block system?

A Fext/6mΔt

B Fext/2mΔt

C 2Fext/mΔt

D 6Fext/mΔt

Respuesta :

Answer:

A

Explanation:

Trust me the math checks out I just did it

It IS NOT C

The change in velocity of the center of mass of the three-block system

is Fext/6mΔt. Option A is correct.

What is velocity?

The change of displacement with respect to time is defined as the velocity.

velocity is a vector quantity. it is a time-based component. Velocity

at any angle is resolved to get its component of x and y-

direction.

The given data in the problem is;

The sum of all the masses is 6m.

[tex]\rm F_{ext}[/tex] is the force exerted to the left on the rightmost block

Δt is the time interval

is the change in the velocity

From Newton's second law, The change in the velocity is

[tex]\rm I = \triangle P \\\\ F \triangle t =m \triangle v \\\\ F_{ext} \triangle t =6m \triangle v \\\\ \triangle v = \frac{ F_{ext} }{6m} \triangle t[/tex]

The change in velocity of the center of mass of the three-block system

is Fext/6mΔt.

Hence option A is correct.

To learn more about the velocity refer to the link ;

https://brainly.com/question/862972