Answer:
[tex]V_y = 16.44\ m/s[/tex]
[tex]V_y = 7.32\ m/s[/tex]
Explanation:
Given
[tex]\theta = 24[/tex]
[tex]Velocity\ (V) = 18m/s[/tex]
Required
Determine the vertical and horizontal components
The vertical (Vy) and horizontal (Vx) components is calculated as thus:
[tex]V_x = Vcos\theta[/tex]
[tex]V_y = Vsin\theta[/tex]
Calculating Vertical Components:
[tex]V_y = Vsin\theta[/tex]
[tex]V_y = 18 * sin24[/tex]
[tex]V_y = 18 * 0.40673664307[/tex]
[tex]V_y = 7.32125957526[/tex]
[tex]V_y = 7.32\ m/s[/tex] --- Approximated
Calculating Horizontal Components:
[tex]V_x = Vcos\theta[/tex]
[tex]V_x = 18 * cos24[/tex]
[tex]V_x = 18 * 0.91354545764[/tex]
[tex]V_x = 16.4438182375[/tex]
[tex]V_x = 16.44\ m/s[/tex] --- Approximated
