Given:
The vertices of ABCD are A(2,3), B(5,6), C(8,6) and D(8,3).
The vertices of A'B'C'D' are A'(-2,6), B'(-5,3), C'(-8,3) and D'(-8,6).
To find:
The sequence of transformation is needed to carry ABCD onto its image A’B’C’D.
Solution:
The vertices of ABCD are A(2,3), B(5,6), C(8,6) and D(8,3).
If figure ABCD translated by the rule, [tex](x,y)\to (x,y-9)[/tex], then
[tex]A(2,3)\to A_1(2,-6)[/tex]
[tex]B(5,6)\to B_1(5,-3)[/tex]
[tex]C(8,6)\to C_1(8,-3)[/tex]
[tex]D(8,3)\to D_1(8,-6)[/tex]
Then the figure rotated 180 degrees clockwise about the origin. So,
[tex](x,y)\to (-x,-y)[/tex]
[tex]A_1(2,-6)\to A'(-2,6)[/tex]
[tex]B_1(5,-3)\to B'(-5,3)[/tex]
[tex]C_1(8,-3)\to C'(-8,3)[/tex]
[tex]D_1(8,-6)\to D'(-8,6)[/tex]
So, the required sequence of transformation that is needed to carry ABCD onto its image A’B’C’D is " A translation by the rule [tex](x,y)\to (x,y-9)[/tex] and then a 180° clockwise rotation about the origin".
Therefore, the correct option is D.
