The mean absolute deviation of the dataset 4 6 12 8 10 10 6 8 is 2
The data values are given as:
4 6 12 8 10 10 6 8
Start by calculating the mean using:
Mean = Sum/Count
So, we have:
[tex]\bar x = (4 +6+ 12+ 8+ 10+ 10+ 6+ 8)/8[/tex]
Evaluate
[tex]\bar x = 8[/tex]
The mean absolute deviation (D) is then calculated using:
[tex]D = \frac{\sum |x - \bar x|}{n}[/tex]
So, we have:
D = |(4 - 8) |+ |(6 -8)| + |(12 -8)| + |(8 -8)| + |(10- 8)| + |(10- 8)| + |(6 -8)| + |(8 - 8)|/8
Evaluate
D = 2
Hence, the mean absolute deviation of the dataset is 2
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