Answer: 7
Explanation:
50 ml 0.125 M KOH = (50 * 0.125) = 6.25 ml 1 M KOH
similarly 50 ml 0.125 M HCl = 6.25 ml 1 M HCl
so KOH will fully neutralize the HCl so the pH of the medium will be 7
H+ + OH- = H2O
so Kw = [H=][OH-]
= [H+]^2 = 10-14
SO [H+] = 10-7
pH = -log [H+]
pH = -log[10-7]
pH = 7
