Complete Question
According to a survey, 74% of households said that they have never purchased organic fruits or vegetables. Suppose that this result is true for the current population of households. a. Let x be a binomial random variable that denotes the number of households in a random sample of 10 who have never purchased organic fruits or vegetables. What are the possible values that x can assume? Integers to . b. Find to 3 decimal places the probability that exactly 6 households in a random sample of 10 will say that they have never purchased organic fruits or vegetables. Use the binomial probability distribution formula. Probability
Answer:
a
The possible value of x is 0, 1 ,2,3,4,5,6,7,8,9,10
b
[tex]P(X = 6) = 0.158 [/tex]
Step-by-step explanation:
From the question we are told that
The proportion that stated that they have not purchased organic fruits or vegetables is [tex]p =0.74[/tex]
The sample size is n = 10
The possible value x can take is 0, 1 ,2,3,4,5,6,7,8,9,10
Generally the probability that exactly 6 households in a random sample of 10 will say that they have never purchased organic fruits or vegetables is mathematically represented as
[tex]P(X = 6) = ^nC_6 * p^{6}* (1-p)^{n-6}[/tex]
Here C denotes combination
So
[tex]P(X = 6) = ^{10}6 * (0.74)^{6}* (1-0.74)^{10-6}[/tex]
=> [tex]P(X = 6) = 0.158 [/tex]
