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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Respuesta :

Given:

The inequality is

[tex]-3(2x-5)<5(2-x)[/tex]

To find:

The correct representations of the given inequality.

Solution:

We have,

[tex]-3(2x-5)<5(2-x)[/tex]

Using distributive property, we get

[tex]-3(2x)-3(-5)<5(2)+5(-x)[/tex]

[tex]-6x+15<10-5x[/tex]

Therefore, the correct option is C.

Isolate variable terms.

[tex]15-10<6x-5x[/tex]

[tex]5<x[/tex]

It means, the value of x is greater than 5.

Since 5 is not included in the solution set, therefore, there is an open circle at 5.

So, the graphical represents of the solution is a A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Therefore, the correct option is D.

trinistargaming

Answer:

C.)–6x + 15 < 10 – 5x

D.)A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Hope this helps and have a nice day :)

Step-by-step explanation:

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