Respuesta :

Answer:

Step-by-step explanation:

(-b±√b²-4ac)/2a

(4±√-4²-4(2)(3))/2(2)

(4±√16-24)/4

(4±√8)/4

=4+√8    ║4-√8

 --------      --------

    4             4

idont know kung tama ba ito

or

(2x-3) (x-1)=0

2x-3=0  x-1=0

2x=3        x=1

x=3/2     x=1

okpalawalter8

We have that Solution to the quadratic equation 2x² - 4x + 3 = 0​ is

Root [tex]x= 1 + 0.707i[/tex]

Root [tex]y= 1 - 0.707i[/tex]

From the question we are told that

2x² - 4x + 3 = 0​

Generally the equation for solving Quadratic equation is  is mathematically given as

([tex](x,y)=\pm b\frac{\sqrt{}b^2-4ac}{2a}\\\\(x,y)=\pm b\frac{\sqrt{(-4)^2-4*2*3}}{2*2}[/tex]

From the Deductions

Root x= 1 + 0.707i

Root y= 1 - 0.707i

Therefore

Solution to the quadratic equation 2x² - 4x + 3 = 0​ is

Root [tex]x= 1 + 0.707i[/tex]

Root [tex]y= 1 - 0.707i[/tex]

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